8xy^2+2y^2-5=0

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Solution for 8xy^2+2y^2-5=0 equation:


Simplifying
8xy2 + 2y2 + -5 = 0

Reorder the terms:
-5 + 8xy2 + 2y2 = 0

Solving
-5 + 8xy2 + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 8xy2 + 5 + 2y2 = 0 + 5

Reorder the terms:
-5 + 5 + 8xy2 + 2y2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 8xy2 + 2y2 = 0 + 5
8xy2 + 2y2 = 0 + 5

Combine like terms: 0 + 5 = 5
8xy2 + 2y2 = 5

Add '-2y2' to each side of the equation.
8xy2 + 2y2 + -2y2 = 5 + -2y2

Combine like terms: 2y2 + -2y2 = 0
8xy2 + 0 = 5 + -2y2
8xy2 = 5 + -2y2

Divide each side by '8y2'.
x = 0.625y-2 + -0.25

Simplifying
x = 0.625y-2 + -0.25

Reorder the terms:
x = -0.25 + 0.625y-2

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